By Larry Davis

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0. * 1 Til T is superstable if R°°(X) is defined for all A. A rather different kind of rank, the U-rank (of Lascar) can be defined for complete types pe S (A) in a stable theory: U(p) > a + 1 if p has a forking extension q such that U(q) > a. It turns out that T is superstable if and only if U(p) < «*> for all p. Both ranks R°° and U reflect forking in a superstable theory: namely for R = R°° or U and p <^ q complete types, R(p) = R(q) just if q is a nonforking extension of p. 4. ) equipped with possibly additional structure such that the theory of this structure is stable.

We must show that every nonzero element of R has an inverse in R. Let re R r & 0. Now Ker r is a G-invariant subgroup of A, so must be finite. By Morley rank considerations r is surjective. Let therefore b e A be such that r -b = a where a is the generic element of A chosen above. By (**) there is s e R such that sa = b. So rs(a) = a. By (**) again rs = 1. This shows that R is a field. Clearly G <^ R, and the map r —» ra is an additive isomorphism between R and A. 15. Let G be a connected co-stable group of finite Morley rank which is solvable but non nilpotent.

X. such that X is greatest. Easily X is a subgroup of G. 9 even X-X = X. Zil'ber remarkably proved a generalization of this result to co-stable groups of finite Morley rank. Hrushovski in a paper in this volume proves the result in an even more general context. Here we give Zil'ber's proof. The problem of course is that in the general situation of co-stable groups we have no geometry (at least a priori), so no notion of irreducible. Zil'ber finds a substitute for this: he calls definable Xd G indecomposable if for any definable subgroup H of G, either IX/HI = 1 or IX/HI is infinite.